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=-9Y^2-12Y
We move all terms to the left:
-(-9Y^2-12Y)=0
We get rid of parentheses
9Y^2+12Y=0
a = 9; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·9·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*9}=\frac{-24}{18} =-1+1/3 $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*9}=\frac{0}{18} =0 $
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